In robotic pickβandβplace applications the gripper must generate enough normal force to keep a part securely between its jaws. The required clamping force depends on the partβs weight and the friction that develops at the contact surfaces.
The basic relationship is derived from the equilibrium of forces: the frictional force (ΞΌ N) on each jaw must at least balance half of the partβs weight (m g/2). Solving for the total normal force gives the formula below.
m = part mass (kg)
g = 9.81β―m/sΒ² (gravity)
mu = coefficient of friction (unitless)
Design practice adds a safety factor (SF) to compensate for uncertainties such as surface contamination or dynamic loads. The final command to the robotβs actuator is therefore F_{required}=SFtimesF_{text{clamp}}.
How do I calculate the clamping force for a robotic gripper?
What factors affect the required gripper force?
How do I determine the coefficient of friction for my application?
Can this formula be used for all types of parts?
What is the significance of half the part’s weight in the formula?
How does gravity affect the clamping force calculation?
Is there a maximum limit for gripper force?
Results are for informational purposes only and do not constitute professional advice.
